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Robredo to meet Anderson for Casablanca crown

2:51 PM, Apr 13, 2013   |    comments
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Casablanca, Morocco (Sports Network) - Tommy Robredo of Spain and South Africa's Kevin Anderson were semifinal winners Saturday and will meet for the title at the Moroccan Grand Prix.

Robredo rebounded from a very sluggish start to earn a 1-6, 6-3, 6-2 victory over top-seeded Stanislas Wawrinka of Switzerland, while the second-seeded Anderson followed with a similar result by rallying for a 2-6, 6-4, 6-2 triumph over Martin Klizan of Slovakia.

Wawrinka raced out to a 5-0 lead in the first semifinal, but the 2010 Casablanca champ was unable to sustain the momentum. Robredo regrouped in the second set and broke serve twice before dominating the third set with a trio of breaks.

The 72nd-ranked Robredo improved to 5-1 lifetime against Wawrinka and also reached the Casablanca final for the second time. He lost to Guillermo Canas back in 2001.

Robredo will be trying for his 11th overall ATP World Tour title and 10th on clay. He hasn't won a tournament since capturing the Santiago crown in February 2011 and owns a career record of 10-7 in finals.

Anderson is 2-2 all-time in title matches, including a loss to Bernard Tomic in the Sydney season-opener this year. His last title came in March 2012 in Delray Beach. He will play in a tour-level final on clay for the first time.

Robredo, who is working his way back from a leg injury that sidelined him for five months last year, has never played Anderson.

Sunday's winner will earn $96,000.

The Sports Network

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